A Binary Indexed (Fenwick) Tree is a data structure that provides efficient methods for implementing dynamic cumulative frequency tables.
This Fenwick Tree data structure uses many bit manipulation techniques. In this visualization, we will refer to this data structure using the term Fenwick Tree (usually abbreviated as 'FT') as the abbreviation 'BIT' of Binary Indexed Tree is usually associated with the usual bit manipulation.
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Suppose that we have a multiset of integers s = {2,4,5,6,5,6,8,6,7,9,7} (not necessarily sorted). There are n = 11 elements in s. Also suppose that the largest integer that we will ever use is m = 10 and we never use integer 0. For example, these integers represent student (integer) scores from [1..10]. Notice that n is independent of m.
We can create a frequency table f from s with a trivial O(n) time loop (recall the first counting pass of counting sort). We can then create cumulative frequency table cf from frequency table f in O(m) time using technique similar to DP 1D prefix sum, e.g., in the table below, cf[5] = cf[4]+f[5] = 2+2 = 4 and afterwards cf[6] = cf[5]+f[6] = 4+3 = 7.
Index/Score/Symbol | Frequency f | Cumulative Frequency cf |
---|---|---|
0 | - | - (index 0 is ignored) |
1 | 0 | 0 |
2 | 1 | 1 |
3 | 0 | 1 |
4 | 1 | 2 |
5 | 2 | 4 == cf[4]+f[5] |
6 | 3 | 7 == cf[5]+f[6] |
7 | 2 | 9 |
8 | 1 | 10 |
9 | 1 | 11 |
10 == m | 0 | 11 == n |
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With such cumulative frequency table cf, we can perform Range Sum Query: rsq(i, j) to return the sum of frequencies between index i and j (inclusive), in efficient O(1) time, again using the DP 1D prefix sum (i.e., the inclusion-exclusion principle). For example, rsq(5, 9) = rsq(1, 9) - rsq(1, 4) = 11-2 = 9. As these keys: 5, 6, 7, 8, and 9 represent scores, rsq(5, 9) means the total number of students (9) who scored between 5 to 9, inclusive.
Index/Score/Symbol | Frequency f | Cumulative Frequency cf |
---|---|---|
0 | - | - (index 0 is ignored) |
1 | 0 | 0 |
2 | 1 | 1 |
3 | 0 | 1 |
4 | 1 | 2 == rsq(1, 4) |
5 | 2 | 4 |
6 | 3 | 7 |
7 | 2 | 9 |
8 | 1 | 10 |
9 | 1 | 11 == rsq(1, 9) |
10 == m | 0 | 11 == n |
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A dynamic data structure need to support (frequent) updates in between queries. For example, we may update (add) the frequency of score 7 from 2 → 5 (e.g., 3 more students score 7) and update (subtract) the frequency of score 9 from 1 → 0 (e.g., 1 student who previously scored 9 is found to have plagiarized the work and is now penalized to 0, i.e., removed from the scores), thereby updating the table into:
Index/Score/Symbol | Frequency f | Cumulative Frequency cf |
---|---|---|
0 | - | - (index 0 is ignored) |
1 | 0 | 0 |
2 | 1 | 1 |
3 | 0 | 1 |
4 | 1 | 2 |
5 | 2 | 4 |
6 | 3 | 7 |
7 | 2 → 5 | 9 → 12 |
8 | 1 | 10 → 13 |
9 | 1 → 0 | 11 → 13 |
10 == m | 0 | 11 → 13 == n |
A pure array based data structure for implementing this dynamic cumulative frequency table will need O(m) per update operation. Can we do better?
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Introducing: Fenwick Tree data structure.
There are three mode of usages of Fenwick Tree in this visualization.
The first mode is the default Fenwick Tree that can handle both Point Update (PU) and Range Query (RQ) in O(log n) where n is the largest (integer) index/key in the data structure. Remember that the actual number of keys in the data structure is denoted by another variable m. We abbreviate this default type as PU RQ that simply stands for Point Update Range Query.
This clever arrangement of integer keys idea is the one that originally appears in Peter M. Fenwick's 1994 paper.
You can click the 'Create' menu to create a frequency array f where f[i] denotes the frequency of appearance of key i in our original array of keys s.
IMPORTANT: This frequency array f is not the original array of keys s. For example, if you enter {0,1,0,1,2,3,2,1,1,0}, it means that you are creating 0 one, 1 two, 0 three, 1 four, 2 fives, ..., 0 ten (1-based indexing). The largest index/integer key is m = 10 in this example as in the earlier slides.
If you have the original array s of n elements, e.g., {2,4,5,6,5,6,8,6,7,9,7} from the earlier slides (s does not need to be necessarily sorted), you can do an O(n) pass to convert s into frequency table f of n indices/integer keys. (We will provide this alternative input method in the near future).
You can click the 'Randomize' button to generate random frequencies of n keys [1..n].
Click 'Go' to iteratively call n operations of update(i, f[i]). (We will provide a faster build FT feature in the near future).
Although conceptually this data structure is a tree, it will be implemented as an integer array called ft that ranges from index 1 to index n (we sacrifice index 0 of our ft array). The values inside the (black outline and white inner) vertices of the Fenwick Tree shown above are the values stored in the 1-based Fenwick Tree ft array.
Currently the edges of this Fenwick Tree are not shown yet. There are two versions of the tree, the interrogation/query tree and the updating Tree.
The values inside the bottom (blue inner) vertices are the values of the frequency array f.
The value stored in index i in array ft (vertex i in the Fenwick Tree), i.e., ft[i] is the cumulative frequency of keys in range [i-LSOne(i)+1 .. i]. Visually, this range is shown by the edges of the (interrogation/query version of) Fenwick Tree.
For a review of LSOne(i) = (i) & -(i) operation, see our bitmask visualization page.
ft[4] = 2 stores the cumulative frequency of keys in [4-LSOne(4)+1 .. 4].
(follow the edge from index 4 back upwards to index 0, plus 1 index).
This is [4-4+1 .. 4] = [1 .. 4] and f[1]+f[2]+f[3]+f[4] = 0+1+0+1 = 2.
ft[6] = 5 stores the cumulative frequency of keys in [6-LSOne(6)+1 .. 6].
(follow the edge from index 6 back upwards to index 4, plus 1 index).
This is [6-2+1 .. 6] = [5 .. 6] and f[5]+f[6] = 2+3 = 5.
The function rsq(j) returns the cumulative frequencies from the first index 1 (ignoring index 0) to index j.
This value is the sum of sub-frequencies stored in array ft with indices related to j via this formula j' = j-LSOne(j). This relationship forms a Fenwick Tree, specifically, the 'interrogation tree' of Fenwick Tree.
We apply this formula iteratively until j is 0.
This function runs is O(log m), regardless of n. Discussion: Why?
We have seen earlier that ft[6] = rsq(5, 6) and ft[4] = rsq(1, 4).
Thus, rsq(6) = ft[6] + ft[6-LSOne(6)] = ft[6] + ft[6-2] =
ft[6] + ft[4] = 5 + 2 = 7.
PS: 4-LSOne(4) = 4-4 = 0.
rsq(i, j) returns the cumulative frequencies from index i to j, inclusive.
If i = 1, we can just use rsq(j) as earlier.
If i > 1, we simply need to return: rsq(j) – rsq(i–1) (Principle of Inclusion-Exclusion).
Discussion: Do you understand the reason?
This function also runs in O(log m), regardless of n. Discussion: Why?
rsq(4, 6) = rsq(6) – [next slide...].
And we have seen earlier that rsq(6) = ft[6]+ft[4] = 5+2 = 7.
rsq(4, 6) = rsq(6) – rsq(3).
We can compute similarly that rsq(3) = ft[3]+ft[2] = 0+1 = 1.
rsq(4, 6) = rsq(6) – rsq(3) = 7 - 1 = 6.
To update the frequency of a key (an index) i by v (v is either positive or negative; |v| does not necessarily be one), we use update(i, v).
Indices that are related to i via i' = i+LSOne(i) will be updated by v when i < ft.size() (Note that ft.size() is m+1 (as we ignore index 0). These relationships form a variant of Fenwick Tree structure called the 'updating tree'.
Discussion: Do you understand this operation and on why we avoided index 0?
This function also runs in O(log m), regardless of n. Discussion: Why?
The second mode of Fenwick Tree is the one that can handle Range Update (RU) but only able to handle Point Query (PQ) in O(log n).
We abbreviate this type as RU PQ.
Create the data and try running the Range Update or Point Query algorithms on it. Creating the data for this type means inserting several intervals. For example, if you enter [2,4],[3,5], it means that we are updating range 2 to 4 by +1 and then updating range 3 to 5 by +1, thus we have the following frequency table: 0,1,2,2,1 that means 0 one, 1 two, 2 threes, 2 fours, 1 five.
The vertices at the top shows the values stored in the Fenwick Tree (the ft array).
The vertices at the bottom shows the values of the data (the frequency table f).
Notice the clever modification of Fenwick Tree used in this RU PQ type: We increase the start of the range by +1 but decrease one index after the end of the range by -1 to achieve this result.
The third mode of Fenwick Tree is the one that can handle both Range Update (RU) and Range Query (RQ) in O(log n), making this type on par with Segment Tree with Lazy Update that can also do RU RQ in O(log n).
Create the data and try running the Range Update or Range Query algorithms on it.
Creating the data is inserting several intervals, similar as RU PQ version. But this time, you can also do Range Query efficiently.
In Range Update Range Query Fenwick Tree, we need to have two Fenwick Trees. The vertices at the top shows the values of the first Fenwick Tree (BIT1[] array), the vertices at the middle shows the values of the second Fenwick Tree (BIT2[] array), while the vertices at the bottom shows the values of the data (the frequency table). The first Fenwick Tree behaves the same as in RU PQ version. The second Fenwick Tree is used to do clever offset to allow Range Query again.
We have a few more extra stuffs involving this data structure.
Unfortunately, this data structure is not yet available in C++ STL, Java API, Python or OCaml Standard Library as of 2020. Therefore, we have to write our own implementation.
Please look at the following C++/Python/Java/OCaml implementations of this Fenwick Tree data structure in Object-Oriented Programming (OOP) fashion:
fenwicktree_ds.cpp | py | java | ml
Again, you are free to customize this custom library implementation to suit your needs.
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Note that if you notice any bug in this visualization or if you want to request for a new visualization feature, do not hesitate to drop an email to the project leader: Dr Steven Halim via his email address: stevenhalim at gmail dot com.
Create - O(m log m)
Create - O(m)
RSQ(i, j)
Update(i, v)